When working with highly dynamic websites, one problem is the view-source doesn’t show the dynamic content that was generated. What you want is a snapshot of the DOM at the time.
I decided to whip one up into my AJAX debugging framework after which Joseph suggested that it be a bookmarklet instead.
Here is the source code:
It still has a bug in that it is rendering the HTML when I passed in text/plain. Here is an alternate:
The problem with that is certain tags are filtered out in the <plaintext> rendering. (You can view source it).
Also, I use the innerHTML since I don’t think Mozilla has an outerHTML property.
Not sure what to do.
One thought on “Showing the rendered source”
Joelâ€™s corner modifies my script.